A) 0.41 M
B) 0.56 M
C) 0.63 M
D) 0.76 M
Correct Answer: D
Solution :
250 mL of\[\frac{M}{4}NaOH\]contains \[=\frac{40}{4}\times \frac{250}{1000}g\] \[=2.5\,g\,NaOH\] Mass of 250 mL of\[NaOH\]solution \[=v\times d\] \[=250\text{ }mL\times 1.05\text{ }gc{{m}^{-3}}=262.5\text{ }g\] After adding 5 g\[NaOH,\]mass of solute\[=7.5\text{ }g\] and solution\[=267.5\text{ }g\] Volume of new solution\[=\frac{267.5}{1.08}=247.7\,mL\] \[=0.2477\text{ }L\] Molarity\[=\frac{7.5}{40}mol\times \frac{1}{0.2477L}=0.76\,M\]You need to login to perform this action.
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