question_answer

Enthalpy of neutralization of\[HF(aq)\]\[HF(aq)+O{{H}^{-}}(aq)\xrightarrow[{}]{{}}{{F}^{-}}(aq)+{{H}_{2}}O(l)\]is \[-68.60\,kJ\,mo{{l}^{-1}}\]and enthalpy change for the reaction is\[-55.83\text{ }kJ\,mo{{l}^{-1}}\].\[{{H}^{+}}(aq)+O{{H}^{-}}(aq)\xrightarrow[{}]{{}}{{H}_{2}}O(l)\] Thus, enthalpy change \[(kJ\,mo{{l}^{-1}})\] for the dissociation is\[HF(aq)\xrightarrow[{}]{{}}{{H}^{+}}(aq)+{{F}^{-}}(aq)\]

A)  \[-12.77\]                          

B)  \[+12.77\]

C)  \[-124.43\]                        

D)  \[+124.43\]