JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2013

  • question_answer
        \[\int{\frac{8x+13}{\sqrt{4x+7}}}dx\]is equal to

    A)  \[\frac{1}{6}(8x+11)\sqrt{4x+7}+C\]

    B)  \[\frac{1}{6}(8x+13)\sqrt{4x+7}+C\]

    C)  \[\frac{1}{6}(8x+9)\sqrt{4x+7}+C\]

    D)  \[\frac{1}{6}(8x+15)\sqrt{4x+7}+C\]

    Correct Answer: A

    Solution :

                    \[I=\int{\frac{8x+13}{\sqrt{4x+7}}}dx=\int{\frac{2(4x+7)-1}{\sqrt{4x+7}}.dx}\] \[=2\int{\sqrt{4x+7}}dx-\int{\frac{dx}{\sqrt{4x+7}}=2.\frac{{{(4x+7)}^{3/2}}}{4.\frac{3}{2}}}\]                                                    \[-\frac{{{(4x+7)}^{1/2}}}{4.\frac{1}{2}}+C\] \[=\frac{1}{3}(4x+7)\sqrt{4x+7}-\frac{1}{2}\sqrt{4x+7}+C\] \[=\frac{\sqrt{4x+7}}{6}.(8x+11)+C\]


You need to login to perform this action.
You will be redirected in 3 sec spinner