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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2013

  • question_answer
    The time period of a freely suspended bar magnet in a field in 2 s. It is cut into two equal parts along its axis, then the time period is

    A)  \[4s\]                                  

    B)  0.5s

    C)  \[2s\]                                  

    D)  0.25 s

    Correct Answer: C

    Solution :

                    We know that, \[T=2\pi \sqrt{\frac{I}{MB}}\] \[T=2s,\] \[I=\frac{I}{2}\] \[M=\frac{M}{2}\] \[\therefore \]                  \[T=2\pi \sqrt{\frac{I}{MB}}\] \[\Rightarrow \]               \[\frac{T}{T}=\sqrt{\frac{I}{I}\times \frac{M}{M}}=1\] \[\Rightarrow \]               \[T=T\] \[\Rightarrow \]               \[T=2\,s\]


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