A) \[I+A+{{A}^{2}}\]
B) \[I+2A+2{{A}^{2}}\]
C) \[I+A+{{A}^{2}}\]
D) None of these
Correct Answer: B
Solution :
\[\because \]\[(I-A)f(A)=I+A\] \[\Rightarrow \]\[f(A)=(I+A){{(I-A)}^{-1}}=(I+A)\] \[\therefore \]\[(I+A+{{A}^{2}})=I+A+{{A}^{2}}+A+{{A}^{2}}+{{A}^{3}}\] \[=I+2A+2{{A}^{2}}\]You need to login to perform this action.
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