A) \[x+\sqrt{3}y=3\]
B) \[\sqrt{3}x+y=3\]
C) \[x+y=\sqrt{3}\]
D) None of these
Correct Answer: B
Solution :
\[\because \]\[n(S)=6\times 6\times 6\times 6={{6}^{4}}\] Number of favorable ways\[{{=}^{6}}{{C}_{4}}=\frac{6\times 5}{2}=15\] \[\therefore \]Required probability \[=\frac{15}{6\times 216}=\frac{5}{2\times 216}=\frac{5}{432}\]You need to login to perform this action.
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