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JAMIA MILLIA ISLAMIA Jamia Millia Islamia Solved Paper-2013

  • question_answer
    10 g of a radioactive isotope is reduced to 1.25 s in 12 yr. Therefore, half-life period of the isotope is

    A)  3yr                                        

    B)  4yr

    C)  8yr                                        

    D)  24yr

    Correct Answer: B

    Solution :

                    \[[R]=\frac{{{[R]}_{0}}}{{{2}^{n}}}\] \[\therefore \]  \[1.25=\frac{10}{{{2}^{n}}}\]or\[{{2}^{n}}=\frac{10}{1.25}=8={{2}^{3}}\] Hence,      \[n=3\] 3 half-lives \[=12\,yr\]or \[{{t}_{1/2}}=4\,yr\]


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