A) \[\frac{4}{3}\]
B) \[4\mu F\]
C) \[10\mu F\]
D) \[8\mu F\]
Correct Answer: C
Solution :
\[{{V}_{p}}=\frac{GM}{\sqrt{{{R}^{2}}+4{{R}^{2}}}}\] \[=-\frac{GM}{\sqrt{5}R}\] \[{{V}_{0}}=-\frac{GM}{R}\] \[\frac{1}{2}m{{V}^{2}}=m({{V}_{p}}-{{V}_{0}})\] \[V=\sqrt{2({{V}_{p}}-{{V}_{0}})}\] Hence, maximum value of given expression is .You need to login to perform this action.
You will be redirected in
3 sec