A) mutually, exclusive
B) independent as well as mutually exhaustive
C) independent
D) dependent only on\[A\]
Correct Answer: C
Solution :
Given that, \[P(A)=2/3,\,\,P(B)=1/2,\,\,P(A\cup B)=5/6\] \[\therefore \] \[P(A\cup B)=P(A)+P(B)-P(A\cap B)\] \[\Rightarrow \] \[P(A\cap B)=2/3+1/2-5/6\] \[=7/6-5/6\] \[=1/3\] Now,\[P(A)\times P(B)=2/3\times 1/2\] \[=1/3=P(A\cap B)\] \[\Rightarrow \]\[A\]and\[B\]are independent events.You need to login to perform this action.
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