A) \[0.60\,\,A{{m}^{2}}\]
B) \[0.45\,\,A{{m}^{2}}\]
C) \[0.30\,\,A{{m}^{2}}\]
D) \[0.15\,\,A{{m}^{2}}\]
Correct Answer: C
Solution :
Magnetic dipole moment of a current carrying circular coil is given by \[M=Ni\,\,A=N\,\,i\,\,\pi \,\,{{r}^{2}}\] Given,\[N=20,\,\,i=3A,\,\,r=4\,\,cm=0.04\,\,m\] \[\therefore \] \[M=20\times 3\times 3.14\times {{(0.04)}^{2}}\] \[\Rightarrow \] \[M=0.3\,\,A-{{m}^{2}}\]You need to login to perform this action.
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