A) \[19\,\,G\]
B) \[20\,\,G\]
C) \[G/20\]
D) \[G/19\]
Correct Answer: D
Solution :
Key Idea: Potential difference across galvanometer and shunt is same. Let \[{{i}_{g}}\] current passes through galvanometer and \[i-{{i}_{g}}\] through shunt\[S\], then \[{{i}_{g}}G=(i-{{i}_{g}})S\] \[S=\left( \frac{{{i}_{g}}}{i-{{i}_{g}}} \right)G\] Given, \[{{i}_{g}}=5A,\,\,100\,\,A,\] \[\therefore \] \[S=\left( \frac{5}{100-5} \right)G=\frac{G}{19}\]You need to login to perform this action.
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