JCECE Engineering JCECE Engineering Solved Paper-2002

  • question_answer
    The voltage of an AC supply varies with time \[(t)\] as \[V=120\sin \,\,100\pi t\cos \,\,100\pi t\]. The maximum voltage and frequency respectively are:

    A) \[120\,\,V,\,\,100\,\,Hz\]

    B) \[120/\sqrt{2}V,\,\,100\,\,Hz\]

    C)  \[60\,\,V,\,\,200\,\,Hz\]

    D)  \[60\,\,V,\,\,100\,\,Hz\]

    Correct Answer: D

    Solution :

    The standard equation for \[AC\] supply voltage is given by                 \[V={{V}_{0}}\sin \omega t\]                                      ? (i) Given,\[V=120\sin 100\pi t\cos 100\pi t\]                 \[V=60[2\sin 100\pi t\cos 100\pi t]\] Using formula\[\sin 2\theta =2\sin \theta \cos \theta \], we get                 \[V=60\sin 200\pi t\]                      ... (ii) Comparing Eqs. (i) and (ii), we get      \[{{V}_{0}}=60\,\,V,\,\,\omega =2\pi n=200\pi ,\,\,n=100\,\,Hz\]


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