JCECE Engineering JCECE Engineering Solved Paper-2002

  • question_answer
    A hole is in the bottom of the tank having water. If total pressure at the bottom is \[3\,\,atm\] \[(1\,\,atm={{10}^{5}}N{{m}^{-2}})\], then velocity of water flowing from hole is:

    A) \[\sqrt{400}m{{s}^{-1}}\]                             

    B)  \[\sqrt{600}m{{s}^{-1}}\]

    C)  \[\sqrt{60}m{{s}^{-1}}\]                              

    D)  \[\sqrt{40}m{{s}^{-1}}\]

    Correct Answer: A

    Solution :

    Let height of water column in the tank be\[h\]. Total pressure \[(P)=\] atmospheric pressure \[({{P}_{0}})+\] pressure due to water column in tank \[(P')\] \[\therefore \]  \[P'=P-{{P}_{0}}=3-1=2\,\,atm\] or            \[h\rho g=2\times {{10}^{5}}\] or            \[h\times {{10}^{3}}\times 10=2\times {{10}^{5}}\] or            \[h=20\,\,cm\] Hence, velocity of water coming from hole \[i.e.,\] velocity of efflux, is                 \[v=\sqrt{2gh}=\sqrt{2\times 10\times 20}\]                    \[=\sqrt{400}m{{s}^{-1}}\]


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