A) \[4.2\times {{10}^{7}}cal/K\]
B) \[4.2cal/K\]
C) \[8.31cal/K\]
D) \[2cal/K\]
Correct Answer: D
Solution :
Key Idea: According to ideal gas equation \[\frac{PV}{T}=R\] where \[R=\]gas constant Value of \[R\] for \[1\] mole of gas\[=8.31\,\,J/mol\,\,K\] \[=1:987\approx 2\,\,cal/K\]
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