A) \[HCN\]
B) \[HCHO\]
C) \[C{{H}_{3}}CN\]
D) \[C{{H}_{3}}Cl\]
Correct Answer: B
Solution :
Key Idea: This is Cannizaro reaction. In this reaction aldehydes, which do not have \[\alpha -\]hydrogen atom undergo disproportionation reaction, half of the molecule are reduced and other half are oxidised. \[\underset{(A)}{\mathop{HCHO}}\,+NaOH\xrightarrow{{}}\underset{sodium\,\,formate}{\mathop{HCOONa}}\,\]\[\underset{methyl\,\,alcohol}{\mathop{+C{{H}_{3}}OH}}\,\]
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