JCECE Engineering JCECE Engineering Solved Paper-2003

  • question_answer
    In a triode valve, when the plate potential is increased from \[200\,\,V\] to \[220\,\,V\] and-grid potential is decreased from \[-0.5\,\,V\] to \[-\text{ }1.3\,\,V,\] there is no change in plate current. The amplification factor of the triode is:

    A) \[25\]                                   

    B) \[14\]

    C)  \[11\]                                  

    D)  \[73\]

    Correct Answer: A

    Solution :

    Amplification factor is defined as the ratio of change in plate potential \[(\Delta {{V}_{p}})\] to produce certain change in plate current \[(\Delta {{i}_{p}})\] to the change in grid potential \[(\Delta {{V}_{g}})\] for the same change in plate current\[i.e,.\]                 \[\mu =-{{\left( \frac{\Delta {{V}_{p}}}{\Delta {{V}_{g}}} \right)}_{\Delta {{i}_{p}}=\text{constant}}}\] Here,     \[\Delta {{V}_{p}}=220-200=20\,\,V\]                 \[\Delta {{V}_{g}}=-1.3-(-0.5)\]                 \[=-0.8\,\,V\]                 \[\mu =-\left( \frac{20}{-0.8} \right)=25\] Note: Amplification factor is unitless and dimensionless.


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