A) \[6400\,\,km\]
B) \[8200\,\,km\]
C) \[4800\,\,km\]
D) \[1600\,\,km\]
Correct Answer: D
Solution :
Acceleration due to gravity at a height \[h\] is given by \[g'=g\left( 1-\frac{2h}{R} \right)\] ? (i) At height\[h,\,\,g'=\frac{g}{2}\] (given) Thus, Eq. (i) becomes \[\therefore \] \[\frac{g}{2}=g\left( 1-\frac{2h}{R} \right)\] or \[\frac{1}{2}=1-\frac{2h}{R}\] or \[\frac{2h}{R}=1-\frac{1}{2}=\frac{1}{2}\] or \[h=\frac{R}{4}=\frac{6400}{4}=1600\,\,km\]You need to login to perform this action.
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