A) \[\frac{n\,\,h}{3\,\,\pi }\]
B) \[\frac{n\,\,h}{2\,\,\pi }\]
C) \[\frac{h}{4\pi }\]
D) \[\sqrt{l(l+1)}\cdot \frac{h}{2\pi }\]
Correct Answer: B
Solution :
According to Bohr's theory, angular momentum of an orbit is always a multiple of \[\frac{h}{2\pi },i.e.,\]equal to\[\frac{n\,\,h}{2\,\,\pi }\].
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