A) \[2\]
B) \[2.5\]
C) \[1.5\]
D) \[0.5\]
Correct Answer: B
Solution :
Key Idea: Write electronic configuration of \[O_{2}^{+}\] according to molecular orbital theory and then calculate bond order. \[O_{2}^{+}=8+8-1=15\] \[\sigma 1{{s}^{2}},\,\,{{\sigma }^{*}}1{{s}^{2}},\,\,\sigma 2{{s}^{2}},\,\,{{\sigma }^{*}}2{{s}^{2}},\,\,\sigma 2p_{z}^{2},\,\,\pi 2p_{x}^{2},\] \[\pi 2p_{y}^{2},\,\,{{\pi }^{*}}2p_{x}^{1}\] Bond order \[=\frac{1}{2}\] [number of bonding electrons\[-\]number of anti bonding electrons] \[=\frac{1}{2}(10-5)=\frac{5}{2}=2.5\]
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