A) oxidation of\[Sn\]
B) reduction of\[HgC{{l}_{2}}\]
C) formation of amalgam
D) oxidation of\[Hg\]
Correct Answer: B
Solution :
Key Idea: Write the equation to find composition of black colour. \[2HgC{{l}_{2}}+SnC{{l}_{2}}\xrightarrow{{}}H{{g}_{2}}C{{l}_{2}}+SnC{{l}_{4}}\] \[H{{g}_{2}}C{{l}_{2}}+SnC{{l}_{2}}\xrightarrow{{}}\underset{black}{\mathop{2Hg}}\,+SnC{{l}_{4}}\] \[\therefore \]Reduction of \[HgC{{l}_{2}}\] to \[Hg\] results in formation of black coloured mercury.
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