A) \[{{H}_{2}}O\]
B) \[AlC{{l}_{3}}\]
C) \[RN{{H}_{2}}\]
D) \[N{{H}_{3}}\]
Correct Answer: B
Solution :
Key Idea: Electron acceptors are Lewis acid (i) \[{{H}_{2}}\overset{\bullet \,\,\bullet }{\mathop{O}}\,,\,\,R-\overset{\bullet \,\,\bullet }{\mathop{N}}\,{{H}_{2}}\]and \[\overset{\bullet \,\,\bullet }{\mathop{N}}\,{{H}_{3}}\] are electron donors and Lewis acid. (ii) \[AlC{{l}_{3}}\] is electron deficient compound and is electron acceptor. So it is Lewis acid.
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