A) \[4/13\]
B) \[1/26\]
C) \[5/52\]
D) \[5/221\]
Correct Answer: D
Solution :
Let \[{{E}_{1}}=\]Event of getting an ace card \[\therefore \] \[P({{E}_{1}})=\frac{4}{52}\] And \[{{E}_{2}}=\]Event of getting an coloured card \[P({{E}_{2}})=\frac{15}{51}\] \[\therefore \]Required probability\[=\frac{4}{52}\times \frac{15}{51}\] \[=\frac{5}{221}\]You need to login to perform this action.
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