A) \[1\,\,mg\]
B) \[3.6\,\,kg\]
C) \[3.3\,\,kg\]
D) \[1\,\,kg\]
Correct Answer: B
Solution :
From Faraday's law of electrolysis \[m=zq\] ... (i) where, \[z\] is electrochemical equivalent, and \[q\] is charge. Also, Energy per\[\sec =qV\] or \[E=qV\] \[q=\frac{E}{V}=\frac{3.6\times {{10}^{8}}}{33}\] ? (ii0 From Eqs. (i) and (ii), we get \[m=\frac{0.33\times {{10}^{-6}}\times 3.6\times {{10}^{8}}}{33}=3.6\,\,kg\]You need to login to perform this action.
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