JCECE Engineering JCECE Engineering Solved Paper-2004

  • question_answer
    A satellite is evolving around the earth in a circular orbit of radius 4 times that of the parking orbit, The time period of the satellite is:

    A) \[16\,\,days\]                   

    B) \[2\,\,days\]

    C) \[4\,\,days\]                     

    D)  \[8\,\,days\]

    Correct Answer: D

    Solution :

    Key Idea: Time period of parking orbit is 1 day. From Kepler's third law                 \[{{T}^{2}}=k{{R}^{3}}\] where, \[T\] is time period and \[R\] is radius of earth. Given,\[{{T}_{1}}=1\,\,day,\,\,{{R}_{2}}=4{{R}_{1}}\] \[\therefore \]  \[\frac{{{T}_{2}}}{1}={{\left( \frac{4{{R}_{1}}}{{{R}_{1}}} \right)}^{3/2}}\] \[\Rightarrow \]               \[{{T}_{2}}={{(4)}^{3/2}}=8\,\,days\]


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