A) \[{{S}_{N}}1\] mechanism
B) \[{{S}_{N}}2\] mechanism
C) any of [b] and [b]
D) none of the above
Correct Answer: A
Solution :
Key Idea: (i) Alkyl halides undergo nucleophilic substitution. (ii) \[{{3}^{o}}\]alkyl halides undergo \[{{S}_{N}}2\] reaction mechanism. (iii) \[{{3}^{o}}\] alkyl halides undergo 5^1 reaction mechanism. \[C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-Cl\]\[({{3}^{o}}-\]butyl chloride) It is \[{{3}^{o}}\] alkyl halide, so it will undergo \[{{S}_{N}}1\] reaction mechanism. \[{{\mathbf{S}}_{\mathbf{N}}}\mathbf{1}\]mechanism: \[{{H}_{3}}C-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-Cl\xrightarrow[-C{{l}^{-}}]{Slow}{{(C{{H}_{3}})}_{3}}{{C}^{+}}\] \[\xrightarrow[fast]{+O{{H}^{-}}}{{(C{{H}_{3}})}_{3}}C-OH\]
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