A) \[NaCl\]
B) \[CuCl\]
C) \[CuC{{l}_{2}}\]
D) \[CsCl\]
Correct Answer: C
Solution :
Key Idea: (i) More the covalent character, less is boiling point. (ii) Smaller the size of cation, more is polarising power and more is covalent character. Among \[N{{a}^{+}}\](of,\[NaCl)\], \[C{{u}^{+}}\](of\[CuCl)\] (of\[CuC{{l}_{2}})\] and \[C{{s}^{+}}\](of\[CsCl)\]size of\[C{{u}^{2+}}\]is smallest. \[\therefore \]\[CuC{{l}_{2}}\] has highest covalent character.
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