JCECE Engineering JCECE Engineering Solved Paper-2005

  • question_answer
    A bag contains \[5\] white and \[3\] black balls and \[4\] balls are successively drawn out and not replaced. The probability that they are alternately of different colours, is:

    A) \[1/196\]                            

    B) \[2/7\]

    C) \[1/7\]                                 

    D) \[13/56\]

    Correct Answer: C

    Solution :

    Required probability\[=P(WBWB)+P(BWBW)\]                 \[=\frac{^{5}{{C}_{1}}{{\times }^{3}}{{C}_{1}}{{\times }^{4}}{{C}_{1}}{{\times }^{2}}{{C}_{1}}}{^{8}{{C}_{1}}{{\times }^{7}}{{C}_{1}}{{\times }^{6}}{{C}_{1}}{{\times }^{5}}{{C}_{1}}}\]                 \[+\frac{^{3}{{C}_{1}}{{\times }^{5}}{{C}_{1}}{{\times }^{2}}{{C}_{1}}{{\times }^{4}}{{C}_{1}}}{^{8}{{C}_{1}}{{\times }^{7}}{{C}_{1}}{{\times }^{6}}{{C}_{1}}{{\times }^{5}}{{C}_{1}}}\]                 \[=\frac{1}{14}+\frac{1}{14}\]                 \[=\frac{2}{14}=\frac{1}{7}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner