question_answer

The force on a conductor of length (placed in a magnetic field of magnitude B and carrying a current \[i\] is given by \[(\theta \] is the angle, the conductor makes with the direction of \[B)\]:

A) \[F=i\,\,l\,\,B\,\,\sin \,\,\theta \]             

B) \[F={{i}^{2}}l\,\,{{B}^{2}}\sin \theta \]

C) \[F=i\,\,l\,\,B\,\,\cos \theta \]  

D) \[F=\frac{{{i}^{2}}l}{B}\sin \theta \]

Correct Answer: A

Solution :

The general equation for the force acting on a current carrying conductor placed in a magnetic field \[(B)\] is given by \[F=ilB\,\,\sin \,\,\theta \] Note: The expression can also be obtained from Lorentz force equation.