JCECE Engineering JCECE Engineering Solved Paper-2005

  • question_answer
    The rate of a reaction is doubled for every \[{{10}^{o}}\] rise in temperature. The increase in reaction rate as a result of temperature rise from \[{{10}^{o}}\] to \[{{100}^{o}}\] is:

    A) \[112\]                                 

    B) \[512\]

    C) \[400\]                                 

    D) \[614\]

    Correct Answer: B

    Solution :

    Key Idea: The rate of reaction increases by \[{{(2)}^{n}}\]for every \[10{}^\circ \] rise in temperature. \[\therefore \]rate of reaction increase \[512\] times.


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