JCECE Engineering JCECE Engineering Solved Paper-2006

  • question_answer
    Let \[{{T}_{n}}\] denote the number of triangles which can be formed using the vertices of a regular polygon of \[n\] sides. If\[{{T}_{n+1}}-{{T}_{n}}=21\], then n equals:

    A) \[5\]                                     

    B) \[7\]

    C) \[6\]                                     

    D) \[4\]

    Correct Answer: B

    Solution :

    Key Idea: For making a triangle, we needs a three vertices of a triangle.                 \[{{T}_{n+1}}-{{T}_{n}}=21\] \[\Rightarrow \]               \[^{n+1}{{C}_{3}}{{-}^{n}}{{C}_{3}}=21\,\,(\because \,\,{{T}_{n}}{{=}^{n}}{{C}_{3}})\] \[\Rightarrow \]               \[^{n}{{C}_{2}}{{+}^{n}}{{C}_{3}}{{-}^{n}}{{C}_{3}}=21\] \[\Rightarrow \]                      \[^{n}{{C}_{2}}=21\] \[\Rightarrow \]               \[\frac{n(n-1)}{2}=21\] \[\Rightarrow \]    \[{{n}^{2}}-n-42=0\] \[\therefore \]              \[n=7\]


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