JCECE Engineering JCECE Engineering Solved Paper-2006

  • question_answer
    If\[\operatorname{var}(x)=8.25,\,\,\operatorname{var}(y)=33.96\]and\[\operatorname{cov}(x,\,\,y)=10.2\], then the correlation coefficient is:

    A) \[0.89\]                               

    B) \[-0.98\]

    C) \[0.61\]                               

    D) \[-0.16\]

    Correct Answer: B

    Solution :

    Key Idea: If the variance of \[x\] and \[y\] is \[\operatorname{var}(x)\] and \[\operatorname{var}(y)\] and covariance of \[x\] and \[y\] is \[\operatorname{cov}(x,\,\,y)\], then the correlation coefficient is                 \[{{r}_{xy}}=\frac{\operatorname{cov}(x,\,\,y)}{\sqrt{\operatorname{var}(x)\cdot \operatorname{var}(y)}}\]                      \[=\frac{10.2}{16.74}\]                      \[=0.61\] Note: If two variables are independent, then correlation coefficient is zero.


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