A) less at\[{{T}_{1}}\]
B) more at\[{{T}_{1}}\]
C) equally in the two cases
D) cannot say
Correct Answer: A
Solution :
From We in's displacement law \[{{\lambda }_{m}}T=\]constant ... (i) where \[{{\lambda }_{m}}\]corresponds to maximum wavelength, \[T\] is absolute temperature. Also\[,\] \[v=n\lambda \] ? (ii) where \[v\] is velocity, \[n\] the frequency, \[\lambda \] the wavelength. From Eqs. (i) and (ii), we get \[\frac{v}{n}\cdot T=\]constant Given\[{{T}_{1}}<{{T}_{2}}\], hence frequency corresponding to maximum intensity is less at\[{{T}_{1}}\].
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