JCECE Engineering JCECE Engineering Solved Paper-2006

  • question_answer
    A gas is at \[{{27}^{o}}C\]. Its volume is doubled keeping pressure constant, then final temperature is:

    A) \[{{600}^{o}}C\]                               

    B) \[327\,\,K\]

    C) \[{{327}^{o}}C\]                               

    D)  \[{{273}^{o}}C\]

    Correct Answer: C

    Solution :

    Key Idea: Since pressure is constant, gas obeys Charle's law. From Charle's law                 \[\frac{V}{T}=\]constant where \[V\] is volume, \[T\] the temperature. \[\therefore \]  \[\frac{{{V}_{2}}}{{{V}_{1}}}=\frac{{{T}_{2}}}{{{T}_{1}}}\] Given\[{{T}_{1}}={{27}^{o}}C=300\,\,K,\,\,{{V}_{2}}=2{{V}_{1}}\] \[\therefore \]  \[2\times 300={{T}_{2}}\] \[\Rightarrow \]               \[{{T}_{2}}=600\,\,K\] In centigrade\[{{T}_{2}}=600-273={{327}^{o}}C\].


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