JCECE Engineering JCECE Engineering Solved Paper-2006

  • question_answer
    A nucleus \[_{Z}^{A}X\] emits one a and \[2\beta \] particles, then final nucleus is:

    A) \[Y_{Z-2}^{A}\]                                

    B) \[Y_{Z-4}^{A-4}\]

    C) \[Y_{Z}^{A-4}\]                                

    D)  \[X_{Z}^{A}\]

    Correct Answer: C

    Solution :

    Key Idea: \[\beta -\]particles are fast moving electrons. When \[\alpha -\]particle is emitted by an atom, its atomic number decreases by \[2\] and mass number by\[4\]. \[\therefore \]  \[_{Z}^{A}X\xrightarrow{\alpha }_{Z-2}^{A-4}M\] When \[\beta -\]particle is emitted, the atomic number increases by\[1\], while mass number remains unchanged, therefore                 \[_{Z-2}^{A-4}M\xrightarrow{2\beta }_{Z}^{A-4}Y\]


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