A) \[f/2\]
B) \[f\]
C) \[2f\]
D) \[4f\]
Correct Answer: C
Solution :
For a particle executing \[SHM\] the displacement equation is given by \[y=a\sin \omega \,t=a\sin 2\pi ft\] kinetic energy \[KE=\frac{1}{2}m{{v}^{2}}=\frac{1}{2}m{{\left( \frac{dy}{dt} \right)}^{2}}\] where \[\frac{dy}{dt}=2\pi \,\,fa\cos 2\pi ft\] \[\therefore \] \[KE=\frac{1}{2}m\{{{(2\pi fa)}^{2}}{{\cos }^{2}}2\pi ft\}\] \[KE\propto (1+\cos 4\pi ft)\] \[\cos 4\pi ft\] changes periodically with frequency\[2f\].
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