A) \[2\,\,N\]
B) \[2\sqrt{5}N\]
C) \[3\sqrt{2}N\]
D) \[4\sqrt{2}N\]
Correct Answer: B
Solution :
The resultant force is given by \[R=\sqrt{{{A}^{2}}+{{B}^{2}}+2AB\cos \theta }\] Given, \[A=2N,\,\,B=2N,\,\,\theta ={{60}^{o}}\] \[\therefore \] \[R=\sqrt{{{2}^{2}}+{{2}^{2}}+2\times 2\times 2\cos {{60}^{o}}}\] \[\Rightarrow \] \[R=\sqrt{16+4}\] \[\Rightarrow \] \[R=\sqrt{20}\] \[\Rightarrow \] \[R=2\sqrt{5}N\]
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