A) only \[N{{a}_{2}}O\] is formed
B) only \[{{N}_{3}}\] is formed
C) only \[{{O}_{2}}\] is formed
D) all are formed
Correct Answer: D
Solution :
On heating \[NaN{{O}_{3}}\] above \[{{600}^{o}}C\,\,N{{a}_{2}}O,\,\,{{O}_{2}}\] and \[{{N}_{2}}\] all is obtained as: \[4NaN{{O}_{3}}\xrightarrow{{{800}^{o}}C}2N{{a}_{2}}O+5{{O}_{2}}+2{{N}_{2}}\]
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