A) ethanamine
B) methanamine
C) methanamide
D) ethanenitrile
Correct Answer: B
Solution :
When acetamide is treated with \[NaBr\] or \[B{{r}_{2}}/NaOH\], Hofmann degradation reaction takes place and a primary amine is obtained as: \[C{{H}_{3}}CONH+NaOBr\]or\[B{{r}_{2}}/NaOH\xrightarrow{{}}\] \[\underset{\begin{smallmatrix} \text{methyl}\,\,\text{amine} \\ \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,or \\ \text{methanamine} \end{smallmatrix}}{\mathop{C{{H}_{3}}N{{H}_{2}}}}\,+2NaBr+NaHC{{O}_{3}}+{{H}_{2}}O\]
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