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JCECE Engineering JCECE Engineering Solved Paper-2007

  • question_answer
    If\[P(A)=P(B)=P(C)=\frac{1}{4},\] \[P(AB)=P(CB)=0\]and\[P(A\cap C)=\frac{1}{8}\], then \[P(A+B)\] is equal to

    A) \[\frac{5}{8}\]                                   

    B) \[\frac{37}{64}\]

    C) \[\frac{3}{4}\]                                   

    D) \[\frac{1}{2}\]

    Correct Answer: D

    Solution :

    Given\[P(A)=P(B)=P(C)=\frac{1}{4}\]                    \[P(AB)=P(CB)=0\] and                       \[P(A\cap C)=\frac{1}{8}\] Now,                    \[P(A+B)=P(A\cup B)\] \[=P(A)+P(B)-P(A\cap B)=\frac{1}{4}+\frac{1}{4}-0=\frac{1}{2}\]


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