JCECE Engineering JCECE Engineering Solved Paper-2007

  • question_answer
    If equation of a sound wave is\[y=0.0015\sin (62.8x+314t)\] then its wavelength will be

    A) \[0.1\,\,unit\]                   

    B) \[2\,\,unit\]

    C) \[0.3\,\,unit\]                   

    D)  \[0.2\,\,unit\]

    Correct Answer: A

    Solution :

    Key Idea: The standard equation of sound wave is                 \[y=a\sin 2\pi \left( \frac{x}{\lambda }+\frac{t}{T} \right)\] where \[a\] is amplitude, \[\lambda \] is wavelength and \[T\] is time period. Given, equation of wave is                 \[y=0.0015\sin (62.8x+314t)\]     ... (i) Comparing given Eq. (i) with standard wave equation, we get                 \[\frac{2\pi }{\lambda }=62.8\] \[\Rightarrow \]               \[\lambda =\frac{2\pi }{62.8}=\frac{2\times 3.14}{62.8}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner