A) \[2\]
B) \[4\]
C) \[\frac{1}{2}\]
D) \[1\]
Correct Answer: A
Solution :
Sabine formula for reverberation time is \[T=\frac{0.16\,\,V}{\Sigma \,\,aS}\] where \[V\] is volume of hall in\[{{m}^{3}}\]. \[\Sigma aS={{a}_{1}}{{S}_{1}}+{{a}_{2}}{{S}_{2}}+...\] \[=\]total absorption of the hall (room) Here, \[{{S}_{1}},\,\,{{S}_{2}},\,\,{{S}_{3}}.......\] are surface areas of the absorbers and \[{{a}_{1}},\,\,{{a}_{2}},\,\,{{a}_{3}}......\] are their respective absorption coefficients. \[\therefore \] \[\frac{T'}{T}=\frac{V'}{S'}\times \frac{S}{V}=\frac{{{(2)}^{3}}}{{{(2)}^{2}}}=\frac{8}{4}=2\] Here, \[T'=2T=2\times 1=2\,\,s\]
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