JCECE Engineering JCECE Engineering Solved Paper-2007

  • question_answer
    The change in entropy for the fusion of \[1\] mole of ice is \[[mp\] of ice \[=273\,\,K\], molar enthalpy of fusion for ice\[=6.0\,\,kJ\,\,mo{{l}^{-1}}]\]

    A) \[11.73\,\,J{{K}^{-1}}mo{{l}^{-1}}\]

    B) \[18.84\,\,J{{K}^{-1}}mo{{l}^{-1}}\]

    C)  \[21.97\,\,J{{K}^{-1}}mo{{l}^{-1}}\]

    D)  \[24.47\,\,J{{K}^{-1}}mo{{l}^{-1}}\]

    Correct Answer: C

    Solution :

    Entropy change of fusion       \[\Delta {{S}_{f}}=\frac{\Delta {{H}_{f}}}{T}\]     \[\Delta {{H}_{f}}=60\times {{10}^{3}}J\,\,mo{{l}^{-1}},\,\,T=273\,\,K\]      \[\Delta {{S}_{f}}=\frac{60\times {{10}^{3}}}{273}\]              \[=21.97\,\,J\,\,{{K}^{-1}}mo{{l}^{-1}}\]


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