A) \[[Co{{(N{{H}_{3}})}_{3}}C{{l}_{3}}]\]
B) \[[Co{{(en)}_{3}}]C{{l}_{2}}\]
C) \[[Co{{(en)}_{2}}C{{l}_{2}}]Cl\]
D) \[[Co(en){{(N{{H}_{3}})}_{2}}C{{l}_{2}}]Cl\]
Correct Answer: A
Solution :
Octahedral complexes of type\[[M{{a}_{2}}{{b}_{2}}{{c}_{2}}]\]and\[[Mabcdef],\,\,[M{{(AA)}_{3}}],\]\[[M{{(AA)}_{2}}{{a}_{2}}],\]\[[M(AA){{a}_{2}}{{b}_{2}}],\]\[[M{{(AA)}_{2}}ab]\] and \[[M{{(AA)}_{3}}]\]show optical isomerism due to asymmetric molecules, octahedral complex of type\[[M{{a}_{4}}{{b}_{2}}]\]and\[[M{{a}_{3}}{{b}_{3}}]\]do not show optical isomerism due to presence of plane of symmetry. Hence\[[Co{{(N{{H}_{3}})}_{3}}C{{l}_{3}}]\]will not show optical isomerism.
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