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JCECE Engineering JCECE Engineering Solved Paper-2008

  • question_answer
    When an un polarized light of intensity \[{{I}_{0}}\] is incident on a polarizing sheet, the intensity of the light which does not get transmitted is

    A) \[\frac{1}{2}{{I}_{0}}\]                                  

    B) \[\frac{1}{4}{{I}_{0}}\]

    C) \[zero\]                                               

    D)  \[{{I}_{0}}\]

    Correct Answer: A

    Solution :

    \[I={{I}_{0}}{{\cos }^{2}}\theta \] Intensity of polarized light                 \[=\frac{{{I}_{0}}}{2}\] \[\therefore \]Intensity of un transmitted light                 \[={{I}_{0}}-\frac{{{I}_{0}}}{2}=\frac{{{I}_{0}}}{2}\]


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