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JCECE Engineering JCECE Engineering Solved Paper-2008

  • question_answer
    For the redox reaction \[Zn(s)+C{{u}^{2+}}(0.1\,\,M)\xrightarrow{{}}Z{{n}^{2+}}(1\,\,M)+Cu(s)\] taking place in a cell,\[E_{cell}^{\text{o}}\]is\[1.10\,\,V\].\[{{E}_{cell}}\]for the cell will be\[\left( 2.303\frac{RT}{F}=0.0591 \right)\]

    A) \[2.14\,\,V\]                      

    B) \[1.80\,\,V\]

    C) \[1.07\,\,V\]                      

    D)  \[0.82\,\,V\]

    Correct Answer: C

    Solution :

    \[{{E}_{cell}}=E_{cell}^{o}-\frac{0.0591}{n}\log Q\] \[\underset{0.1\,\,M}{\mathop{C{{u}^{2+}}}}\,+Zn\xrightarrow{{}}\underset{1\,\,M}{\mathop{Z{{n}^{2+}}}}\,+Cu\]                 \[Q=\frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]}=\frac{1}{0.1}=10\]            \[{{E}_{cell}}=1.10-\frac{0.0591}{2}\log 10\]                     \[=1.10-0.295=1.0705\,\,V\]


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