question_answer

In a set of the given reactions, acetic acid yielded a product\[C\]. \[C{{H}_{3}}COOH+PC{{l}_{5}}\xrightarrow{{}}A\]\[A\xrightarrow[anhy\,\,AlC{{l}_{3}}]{{{C}_{6}}{{H}_{6}}}B\xrightarrow[ether]{{{C}_{2}}{{H}_{5}}MgBr}C\]Product \[C\] would be

A) \[C{{H}_{3}}CH(OH){{C}_{6}}{{H}_{5}}\]

B)  \[C{{H}_{3}}-\overset{\begin{smallmatrix}  {{C}_{2}}{{H}_{5}} \\  | \end{smallmatrix}}{\mathop{C}}\,(OH){{C}_{6}}{{H}_{5}}\]

C)  \[C{{H}_{3}}CH(OH){{C}_{2}}{{H}_{5}}\]

D)  \[C{{H}_{3}}CO{{C}_{6}}{{H}_{5}}\]

Correct Answer: B

Solution :

\[C{{H}_{3}}COOH+PC{{l}_{5}}-\underset{(A)}{\mathop{C{{H}_{3}}COCl}}\,\]