A) \[\frac{{{x}^{2}}-{{y}^{2}}}{a-b}=\frac{2xy}{h}\]
B) \[\frac{{{x}^{2}}+{{y}^{2}}}{a+b}=\frac{xy}{2h}\]
C) \[\frac{{{x}^{2}}-{{y}^{2}}}{a-b}=\frac{xy}{h}\]
D) None of these
Correct Answer: A
Solution :
Given equation of pair of lines is \[a{{x}^{2}}+hxy+b{{y}^{2}}=0\] \[\therefore \]Equation of bisector is \[\frac{{{x}^{2}}-{{y}^{2}}}{a-b}=\frac{xy}{h/2}\] \[\Rightarrow \] \[\frac{{{x}^{2}}-{{y}^{2}}}{a-b}=\frac{2xy}{h}\]
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