JCECE Engineering JCECE Engineering Solved Paper-2009

  • question_answer
    If the equation\[({{a}^{2}}+4a+3){{x}^{2}}+({{a}^{2}}-a-2)x\]\[+a(a+1)=0\]has more than two roots, then value of \[a\] is

    A) \[0\]                                     

    B) \[1\]

    C) \[-1\]                                    

    D)  None of these

    Correct Answer: C

    Solution :

    Given equation is \[({{a}^{2}}+4a+3){{x}^{2}}({{a}^{2}}-a-2)x+a(a+1)=0\] Let\[a=-1\], then                 \[0\cdot {{x}^{2}}+0\cdot x-1(-1+1)=0\] \[\Rightarrow \]                                                     \[0=0\] Hence, option  is correct.


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