A) \[{{I}_{0}}\]
B) \[\frac{{{I}_{0}}}{2}\]
C) \[\frac{{{I}_{0}}}{4}\]
D) \[\frac{{{I}_{0}}}{8}\]
Correct Answer: C
Solution :
According to Malus' law \[I={{I}_{0}}{{\cos }^{2}}\theta \] \[={{I}_{0}}({{\cos }^{2}}{{60}^{o}})\] \[={{I}_{0}}\times {{\left( \frac{1}{2} \right)}^{2}}\] \[=\frac{{{I}_{0}}}{4}\]You need to login to perform this action.
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