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JCECE Engineering JCECE Engineering Solved Paper-2009

  • question_answer
    In the conversion of \[B{{r}_{2}}\] to\[BrO_{3}^{-}\], the oxidation number of \[Br\] changes from

    A)  zero to\[+5\]                   

    B)  \[+1\]to\[+5\]

    C)   zero to\[-3\]                   

    D) \[+2\]to\[+5\]

    Correct Answer: A

    Solution :

    Bromine has zero oxidation state because it is in free state                 \[\overset{0}{\mathop{B{{r}_{2}}}}\,\xrightarrow{{}}BrO_{3}^{-}\]                 \[BrO_{3}^{-}\]                 \[x+(-2\times 3)=-1\]                 \[x+(-6)=-1\]                 \[x=+6-1\]                 \[=+5\] So, oxidation number changes from 0 to +5.


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